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(A) When the reflected light is least intense,it means the light is polarized at the Brewster's angle $(i_p)$.According to Brewster's law,$	an i_p =

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$120$

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(A) When the reflected light is least intense,it means the light is polarized at the Brewster's angle $(i_p)$.According to Brewster's law,$	an i_p = \mu = \frac{4}{3}$.Let $d_1$ be the horizontal distance from the observer to the point of reflection on the river surface,and $d_2$ be the horizontal distance from the point of reflection to the tower.From the geometry of the reflection:$	an i_p = \frac{d_1}{30} = \frac{d_2}{60}$.Given $	an i_p = \frac{4}{3}$,we have:$\frac{d_1}{30} = \frac{4}{3} \Rightarrow d_1 = 40 \ m$.$\frac{d_2}{60} = \frac{4}{3} \Rightarrow d_2 = 80 \ m$.The total width of the river is $d = d_1 + d_2 = 40 + 80 = 120 \ m$.

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